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18k^2-70k-8=0
a = 18; b = -70; c = -8;
Δ = b2-4ac
Δ = -702-4·18·(-8)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-74}{2*18}=\frac{-4}{36} =-1/9 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+74}{2*18}=\frac{144}{36} =4 $
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